Homework 2. Chapter 1. For discussion questions there are many points of view. One possible viewpoint follows. 1. If our world is to be self-sustaining, then we have to pay for what we use so that there is no net decrease in resources. This cost must be high enough so that we can replace any renewable resource (e.g. replant trees) or replace a nonrenewable resource (oil) with some equivalent resource (e.g. solar power in various forms). The cost of oil at present merely reflects the cost of production (extraction, refining, transportation) plus whatever profits are realized. This is a result of the fact that no one is presently planning to replace oil with anything. 2. Most people agree that as the standard of living rises around the world, the energy consumption per capita rises. This depends on the definition of standard of living. At present, a high standard of living is equated with high rate of material consumption, so that one is considered to be better off if one has more possessions and uses more energy. Since most developing nations aspire to be like the developed nations, their energy consumption per capita is rising. 3. Open question, requires some soul-searching. Use of public versus private transportation, change in home life style, etc. Chapter 2. Questions 1. (a) When you ride a bicycle your body converts chemical energy (food) to mechanical energy (muscle) plus heat. For bike plus human, mechanical energy is converted to kinetic energy (you accelerate to some velocity) and potential energy, if you climb a hill. You also do work against friction (air resistance, bearing and tire friction) which ulitmately ends up as heat. Most of the energy becomes work done (force x distance) moving you from A to B. (b) A windmill converts the kinetic energy of the air (mass times velocity squared) into mechanical energy. This is used to lift water, thereby changing its potential energy and also giving it kinetic energy. Heat is produced throughout. 2. When an automobile rolls up an incline and stops, some of the kinetic energy (hopefully, most of it!) is converted to potential energy. The potential energy can be converted back into kinetic energy when it rolls downhill. Some energy is converted to heat through friction. 3. Any time that a moving object reverses direction, its velocity must be zero for an extremely short time. However, it is almost always accelerating! Think about a ball bobbing on a spring. The velocity is of the ball is instantaneously zero at the endpoints of the motion, but the spring is still exerting a force on it, so it is accelerating. A ball thrown up is another example. It has a positive velocity going up, which is becoming smaller and then negative as it begins to fall. At the very top of the trajectory, the velocity is zero but the acceleration is always g = 9.8 m/s2. Problems: (It is OK to round "g", the acceleration due to gravity, off to 10 m/s2 but I use 9.8 m/s2 here.) 1. A 2 kg object moving at 3 m/s has kinetic energy KE = 1/2m (v squared) KE = 1/2 (2 kg) (3 m/s squared) = 9 Joules If it were raised to some height it would have potential energy PE = mgh Setting these equal mgh = 9 Joules = (2 kg) (9.8 m/s2) (h) = 9 or h = 9 / (19.8) = 0.45 m 2. Work = force x distance = change in energy In this case KE = (1/2) m (v squared) = Fd = 40 N x 5 m = 200 Joules To get the velocity we have (1/2) (20 kg) (v squared) = 200 J v squared = 200 J/ 10 kg = 20 (m/s)squared v = 4.5 m/s 3. A ball with mass 0.5 kg is dropped 5 m. The final KE is equal to the change in PE which is PE = mgh = (0.5 kg)(9.8 m/s2)(5 m) = 24.5 J Final KE = 24.5 J = (1/2) m v squared = (1/2) (0.5 kg) v squared v squared = 24.5/ 0.25 (m/s) squared v = square root(98) = 9.8 m/s hmmm.... Since ALL OBJECTS accelerate in free fall at 9.8 m/s2, it would take 1 second to fall 5 m, at the end of which, the velocity is 9.8 m/s! It doesn't matter what the mass is. 4. The kinetic energy of any object depends on its velocity squared. If the velocity doubles, the kinetic energy increases by a factor of four. The brakes have to do work (exert a force times a distance) to stop the car, that is to convert its velocity and kinetic energy to zero. In this problem, you are given that the brakes exert a constant force, independent of speed. If the kinetic energy increases by a factor of 4, the distance has to increase by a factor of 4. Mathematically: KE = 1/2 m (50 km/h) squared = F x 10 m (given) at twice the speed: 1/2 m (100 km/h) squared = F x 40 m (answer). It doesn't matter what the force or the mass is.